Відео

I will pretend i understood

This is exactly what a good teacher will tell you - the intricacies of _why_ the harmonic motions equations are that way. If your teacher sucks then I guess this video will be good but otherwise this video is just repeating the textbook.

This channel should be called "The over simplifying dude"

This question may be solved by concept of toppling, or may ne not, if any one know please reply😊😊

I didn't watch the full video but found the problem quite intriguing after the point where he says it's not 30°. So I searched for 1998 physics olympiad and found the question paper. And I must say it's designed so nicely that the 5 sub-questions subtly nudge you towards the final solution. I haven't solved many physics problems for 5-7 years now, but I could solve it in a couple of hours because of all the sub-questions guiding me in the right direction. It felt very satisfying to solve it myself and I must say I wouldn't have been able to do it if the questions weren't framed so beautifully.

HYDRA? feels like ww2 germany? and in turn could that mean some sort of enigma machine is involved?

"Simple" problem

This is so awesome, your explanation is truly easy to grasp. Would love to see how you found out how much energy was lost each time.

I am a neet aspirant even tho I can understand by your simple explanation.... And I did completed the rotational motion chapter so I was connecting the chapter with the video.. Thank you❤

其实没有那么复杂, 几何学定律:三角形的内角和是180度,N边形的内角和是360度, 铅笔:(360/6)/2=30度, 如果是立方体(360/4)/2=45度, 如果是等腰三角形,(180/3)/1=60度, 长条形的东西是(180/2)/1=90度,

Great Video! Does someone know what tool os being used for Animation?

Forgot about the fact that the pencil can be approximated as a sphere

I thought Asia Physics Olympiad is harder

i done it by concept of toppling and angle of repose

Brother love from India I am very amazed to see this that's the reason why I love physics ❤ Thanks for making such a video

Gravity is not a force

when you will upload next video I wait you

this content just make bombastic atmosphere for beginners like me

Shouldn't this simply be MGH to MVV/2? Potential to Kinetic Energy? Unless you're making allowance for friction, thermal losses, air resistance etc, then it's no different from a pendulum in space - What it gains in kinetic energy from falling is sufficient to raise it's CoG to the same height again. That being the case, the angle is anything > 0. The shape should be irrelevant, whether a square, hexagonal, an oval or any other shape. If the collision with the surface does not lose energy, then any angle will result in acceleration, not stability. If potential energy is lost and the only place for it to go is kinetic energy, I think you may have overthought this one and added formulaic components that are not relevant to the calculation. Without losses, a round pencil and a hexagonal pencil of the same mass and rotational distribution on average should start rolling at the same time, and reach the same speed at the same time, though of course you should get a pendulaic result where the shaped pencil is sometimes winning and sometimes losing... Energy cannot be created or destroyed. Exchanging potential energy for kinetic energy means that the speed is the same in both the case of a round pencil and a hex pencil, and both will roll forever if there is any vector of thrust assuming no losses.

Please upload more videos! Subscribed to your channel from 3 devices already,mate! Consistency is key!!!

Nice problem. Still trying to figure out where the 58% value comes from.

I saw a similar question in SS Krotov, but in that question the wedge was at an inclination α with horizontal, and the hexagonal pencil made an angle φ from the plane of the incline. It asked the value of φ for which the pencil just stays in equilibrium. That question was interesting too

Love it ❤thanx dear Do u use Manim for animation ?

Can anyone explain maths of that series, How is the value approaching 0.72 ?

Come back please

got the answer in under a minute too easy commercial engineer on top!

The link of the problem didn't work for is there another way to find it pls?

Video is fine, but physics teacher do tell these stuffs. Why posting some bullshit title,??

gr8 video

Provided the agular displacement should be less than 3 degrees.

Simple harmonic means, there are no higher harmonics.

insane presentation!!

Sir please make a video on the mathematical derivations concerned with the amount of energies lost. One of the best videos I've watched so far!

Quality is amazing, just a thing- don't relly on simulation observations.. try using the things a student can use whilst in an exam, use simulation to depict already proven things by calculating. For example - You said- for smaller angles like 5° you can see it stops.. well not without a simulation I can't see just like that.

Next time check tribological system then solve it (contact mechanics in tribology)

8:51 Can somebody explain, why the kinetic energy is lost by 58%?

why'd you stop making these? its honestly sooo helpful , please come back!

This was so well explained and well made, super underrated. It's very sad to see no more uploads.

As an indian High school student this was too easy to solve

At the end, instead if the Taylor series argument, the derivation can be done for a pendulum using the small angle sine approximation. So in a sense the small angle approximation is mathematically equivalent to dropping off the higher order terms.

Except the most handwavy assumption - the 58% lost in each bump - was totally glossed over. I don't even know how I'd approach figuring that out, I would probably give the answer in terms of some constants like the coefficient of restitution kind of analolgue and maybe make an estimate based on a few "what if" values.

You good?

We solved x"+sin(x)=0 for fun in our mechanics course

As long as the ball is not moving on the flat surface, it's neutral. But as it's moving because potential energy has been converted into kinetic and there is no friction or drag, then, by your definition, the "neutral" configuration is neutral only when it's not moving. ANY change in momentum, a.k.a. force, will make the object move away from it's original center of equilibrium.

tuyệt caf là vời

Nicely done!

"is this table?" Hmm 🧐🤔 im not sure...

Great video! One thing: if I am not mistaken, the plural of equilibrium is equilibria

Highschool teachers won't, college teachers will

It's time to make 5 more videos, Dude.. Stop Overthinking for a while and action